Dictionary Definition
geometrically adv
1 with respect to geometry; "this shape is
geometrically interesting"
User Contributed Dictionary
English
Adverb
- in a geometric manner
- concerning geometrics
Extensive Definition
In mathematics, a geometric
progression, also known as a geometric sequence, is a sequence of numbers where each term after the
first is found by multiplying the previous one by a fixed non-zero
number called the common ratio. For example, the sequence 2, 6, 18,
54, ... is a geometric progression with common ratio 3 and 10, 5,
2.5, 1.25, ... is a geometric sequence with common ratio 1/2. The
sum of the terms of a
geometric progression is known as a geometric series.
Thus, the general form of a geometric sequence
is
- a,\ ar,\ ar^2,\ ar^3,\ ar^4,\ \ldots
and that of a geometric series is
- a + ar + ar^2 + ar^3 + ar^4 + \ldots
where r ≠ 0 is the common ratio and a is a
scale
factor, equal to the sequence's start value.
Elementary properties
The n-th term of a geometric sequence with initial value a and common ratio r is given by- a_n = a\,r^
Such a geometric sequence also follows the
recursive
relation
- a_n = r\,a_ for every integer n\geq 1
Generally, to check whether a given sequence is
geometric, one simply checks whether successive entries in the
sequence all have the same ratio.
The common ratio of a geometric series may be
negative, resulting in an alternating sequence, with numbers
switching from positive to negative and back. For instance
- 1, -3, 9, -27, 81, -243, ...
The behaviour of a geometric sequence depends on
the value of the common ratio. If the common ratio is:
- Positive, the terms will all be the same sign as the initial term.
- Negative, the terms will alternate between positive and negative.
- Greater than 1, there will be exponential growth towards positive infinity.
- 1, the progression is a constant sequence.
- Between -1 and 1 but not zero, there will be exponential decay towards zero.
- −1, the progression is an alternating sequence (see alternating series)
- Less than −1, there will be exponential growth towards infinity (positive and negative).
Geometric sequences (with common ratio not equal
to -1,1 or 0) show exponential
growth or exponential
decay, as opposed to the Linear growth (or
decline) of an arithmetic
progression such as 4, 15, 26, 37, 48, ... (with common
difference 11). This result was taken by T.R.
Malthus as the mathematical foundation of his Principle of
Population. Note that the two kinds of progression are related:
exponentiating each term of an arithmetic progression yields a
geometric progression, while taking the logarithm of each term in a
geometric progression with a positive common ratio yields an
arithmetic progression.
Geometric series
A geometric series is the sum of the numbers in a
geometric progression:
- \sum_^ ar^k = ar^0+ar^1+ar^2+ar^3+\cdots+ar^n \,
We can find a simpler formula for this sum by
multiplying both sides of the above equation by (1-r), and we'll
see that
- (1-r) \sum_^ ar^k = a-ar^\,
since all the other terms cancel. Rearranging
(for r\ne1) gives the convenient formula for a geometric
series:
- \sum_^ ar^k = \frac
Note: If one were to begin the sum not from 0,
but from a higher term, say m, then
- \sum_^n ar^k=\frac
Differentiating this formula
with respect to r allows us to arrive at formulae for sums of the
form
- \sum_^n k^s r^k
For example:
- \frac\sum_^nr^k = \sum_^nkr^=
For a geometric series containing only even
powers of r multiply by (1-r^2):
- (1-r^2) \sum_^ ar^ = a-ar^
- \sum_^ ar^ = \frac
For a series with only odd powers of r
- (1-r^2) \sum_^ ar^ = ar-ar^
and
- \sum_^ ar^ = \frac
Infinite geometric series
An infinite geometric series is an infinite series whose successive terms have a common ratio. Such a series converges if and only if the absolute value of the common ratio is less than one ( | r | \sum_^\infty ar^k = \lim_ = \lim_\frac= \lim_\frac - \lim_Since:
- r^\infty = 0 (when | r |\sum_^\infty ar^k = \frac - 0 = \frac
For example, using numerical values
- \sum_^\infty (191) \left(\frac\right)^k = \frac = 1337
For a series containing only even powers of
r,
- \sum_^\infty ar^ = \frac
and for odd powers only,
- \sum_^\infty ar^ = \frac
In cases where the sum does not start at k =
0,
- \sum_^\infty ar^k=\frac
- \frac\sum_^\infty r^k = \sum_^\infty kr^=
This formula only works for
| r | \sum_^ k r^k = \frac \,;\, \sum_^
k^2 r^k = \frac \, ; \, \sum_^ k^3 r^k = \frac
Also, the infinite
series 1/2 + 1/4 + 1/8 + 1/16 + · · · is an elementary example
of a series that converges
absolutely.
It is a geometric
series whose first term is 1/2 and whose common ratio is 1/2,
so its sum is
- \frac12+\frac14+\frac18+\frac+\cdots=\frac = 1.
It is a geometric
series whose first term is 1/2 and whose common ratio is −1/2,
so its sum is
- \frac12-\frac14+\frac18-\frac+\cdots=\frac = \frac13.
Complex numbers
The summation formula for geometric series
remains valid even when the common ratio is a complex
number. This fact can be used to calculate some sums of
non-obvious geometric series, such as:
- \sum_^ \frac = \frac
The proof of this formula starts with
- \sin(kx) = \frac
- \sum_^ \frac = \frac \left[ \sum_^ \left( \frac \right)^k - \sum_^ \left(\frac\right)^k\right].
This is just the difference of two geometric
series. From here, it is then a straightforward application of our
formula for infinite geometric series to finish the proof.
Product
The product of a geometric progression is the
product of all terms. If all terms are positive, then it can be
quickly computed by taking the geometric
mean of the progression's first and last term, and raising that
mean to the power given by the number of terms. (This is very
similar to the formula for the sum of terms of an arithmetic
sequence: take the arithmetic
mean of the first and last term and multiply with the number of
terms.)
- \prod_^ ar^i = \left( \sqrt\right)^ (if a,r > 0).
Proof:
Let the product be represented by P:
- P=a \cdot ar \cdot ar^2 \cdots ar^ \cdot ar^.
Now, carrying out the multiplications, we
conclude that
- P=a^ r^.
Applying the sum of arithmetic
series, the expression will yield
- P=a^ r^.
- P=(ar^)^.
We raise both sides to the second power:
- P^2=(a^2 r^)^=(a\cdot ar^n)^.
Consequently
- P^2=(a_1 \cdot a_)^ and
- P=(a_1 \cdot a_)^,
which concludes the proof.
Relationship to geometry and Euclid's work
Books VIII and IX of Euclid's Elements analyze geometric progressions and give several of their properties.A geometric progression gains its geometric
character from the fact that the areas of two geometrically
similar plane figures are in "duplicate" ratio to their
corresponding sides; further the volumes of two similar solid
figures are in "triplicate" ratio of their corresponding
sides.
The meaning of the words "duplicate" and
"triplicate" in the previous paragraph is illustrated by the
following examples. Given two squares whose sides have the ratio 2
to 3, then their areas will have the ratio 4 to 9; we can write
this as 4 to 6 to 9 and notice that the ratios 4 to 6 and 6 to 9
both equal 2 to 3; so by using the side ratio 2 to 3 "in duplicate"
we obtain the ratio 4 to 9 of the areas, and the sequence 4, 6, 9
is a geometric sequence with common ratio 3/2. Similarly, give two
cubes whose side ratio is 2 to 5, their volume ratio is 8 to 125,
which can be obtained as 8 to 20 to 50 to 125, the original ratio 2
to 5 "in triplicate", yielding a geometric sequence with common
ration 5/2.
Elements, Book IX
The geometric progression 1, 2, 4, 8, 16, 32, ... (or, in the binary numeral system, 1, 10, 100, 1000, 10000, 100000, ... ) is important in number theory. Book IX, Proposition 36 of Elements proves that if the sum of the first n terms of this progression is a prime number, then this sum times the nth term is a perfect number. For example, the sum of the first 5 terms of the series (1 + 2 + 4 + 8 + 16) is 31, which is a prime number. The sum 31 multiplied by 16 (the 5th term in the series) equals 496, which is a perfect number.Book IX, Proposition 35 proves that in a
geometric series if the first term is subtracted from the second
and last term in the sequence then as the excess of the second is
to the first, so will the excess of the last be to all of those
before it. (This is a restatement of our formula for geometric
series from above.) Applying this to the geometric progression
31,62,124,248,496 (which results from 1,2,4,8,16 by multiplying all
terms by 31), we see that 62 minus 31 is to 31 as 496 minus 31 is
to the sum of 31,62,124,248. Therefore the numbers
1,2,4,8,16,31,62,124,248 add up to 496 and further these are all
the numbers which divide
496. For suppose that P divides 496 and it is not amongst these
numbers. Assume P×Q equals 16×31, or 31 is to Q as P is to 16. Now
P cannot divide 16 or it would be amongst the numbers 1,2,4,8,16.
Therefore 31 cannot divide Q. And since 31 does not divide Q and Q
measures 496, the
fundamental theorem of arithmetic implies that Q must divide 16
and be amongst the numbers 1,2,4,8,16. Let Q be 4, then P must be
124, which is impossible since by hypothesis P is not amongst the
numbers 1,2,4,8,16,31,62,124,248.
See also
References
- Hall & Knight, Higher Algebra, p. 39, ISBN 81-8116-000-2
geometrically in Bulgarian: Геометрична
прогресия
geometrically in Catalan: Progressió
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geometrically in German: Geometrische
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geometrically in Spanish: Progresión
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geometrically in Chinese: 等比数列